| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.09 |
| Score | 0% | 62% |
If side x = 10cm, side y = 15cm, and side z = 10cm what is the perimeter of this triangle?
| 34cm | |
| 35cm | |
| 23cm | |
| 29cm |
The perimeter of a triangle is the sum of the lengths of its sides:
p = x + y + z
p = 10cm + 15cm + 10cm = 35cm
If the base of this triangle is 2 and the height is 4, what is the area?
| 49\(\frac{1}{2}\) | |
| 33 | |
| 45\(\frac{1}{2}\) | |
| 4 |
The area of a triangle is equal to ½ base x height:
a = ½bh
a = ½ x 2 x 4 = \( \frac{8}{2} \) = 4
Solve for a:
3a + 8 = \( \frac{a}{-8} \)
| -2\(\frac{14}{25}\) | |
| \(\frac{12}{35}\) | |
| -\(\frac{5}{6}\) | |
| -\(\frac{4}{5}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
3a + 8 = \( \frac{a}{-8} \)
-8 x (3a + 8) = a
(-8 x 3a) + (-8 x 8) = a
-24a - 64 = a
-24a - 64 - a = 0
-24a - a = 64
-25a = 64
a = \( \frac{64}{-25} \)
a = -2\(\frac{14}{25}\)
A cylinder with a radius (r) and a height (h) has a surface area of:
2(π r2) + 2π rh |
|
π r2h |
|
π r2h2 |
|
4π r2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
If angle a = 24° and angle b = 61° what is the length of angle c?
| 45° | |
| 52° | |
| 95° | |
| 105° |
The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 24° - 61° = 95°