ASVAB Math Knowledge Practice Test 833207 Results

Your Results Global Average
Questions 5 5
Correct 0 3.18
Score 0% 64%

Review

1

The endpoints of this line segment are at (-2, 1) and (2, -3). What is the slope-intercept equation for this line?

41% Answer Correctly
y = -1\(\frac{1}{2}\)x - 3
y = -x - 1
y = 2\(\frac{1}{2}\)x + 1
y = -\(\frac{1}{2}\)x + 0

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, -3) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-3.0) - (1.0)}{(2) - (-2)} \) = \( \frac{-4}{4} \)
m = -1

Plugging these values into the slope-intercept equation:

y = -x - 1


2

If BD = 10 and AD = 11, AB = ?

76% Answer Correctly
6
14
1
13

Solution

The entire length of this line is represented by AD which is AB + BD:

AD = AB + BD

Solving for AB:

AB = AD - BD
AB = 11 - 10
AB = 1


3

If angle a = 64° and angle b = 35° what is the length of angle c?

71% Answer Correctly
81°
64°
121°
53°

Solution

The sum of the interior angles of a triangle is 180°:
180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 64° - 35° = 81°


4

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

61% Answer Correctly

supplementary, vertical

obtuse, acute

acute, obtuse

vertical, supplementary


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


5

If the area of this square is 25, what is the length of one of the diagonals?

68% Answer Correctly
5\( \sqrt{2} \)
8\( \sqrt{2} \)
2\( \sqrt{2} \)
\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{25} \) = 5

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 52 + 52
c2 = 50
c = \( \sqrt{50} \) = \( \sqrt{25 x 2} \) = \( \sqrt{25} \) \( \sqrt{2} \)
c = 5\( \sqrt{2} \)