When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4c - 3c = 7c + 2y + 1 for c in terms of y.
| 14y + 4 | |
| -1\(\frac{2}{3}\)y - \(\frac{1}{3}\) | |
| 5y + 6 | |
| \(\frac{2}{5}\)y + \(\frac{2}{5}\) |