When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -6a + 5a = 9a + 4y - 3 for a in terms of y.
| \(\frac{1}{15}\)y + \(\frac{1}{5}\) | |
| \(\frac{3}{5}\)y + \(\frac{1}{5}\) | |
| 3\(\frac{2}{5}\)y - 1 | |
| -\(\frac{2}{3}\)y - \(\frac{2}{3}\) |