When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 4b + b = -8b - 6z + 3 for b in terms of z.
| -\(\frac{7}{12}\)z + \(\frac{1}{4}\) | |
| \(\frac{5}{6}\)z + \(\frac{1}{3}\) | |
| \(\frac{11}{12}\)z - \(\frac{1}{4}\) | |
| z - 5 |