When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9c + 6c = -6c + 3z + 4 for c in terms of z.
| z + 1\(\frac{3}{5}\) | |
| -\(\frac{1}{5}\)z + \(\frac{4}{15}\) | |
| -\(\frac{1}{10}\)z + \(\frac{4}{5}\) | |
| \(\frac{1}{3}\)z - 2\(\frac{1}{3}\) |