When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c - 2c = 9c - 2z + 8 for c in terms of z.
| -\(\frac{2}{3}\)z + \(\frac{1}{9}\) | |
| 1\(\frac{1}{3}\)z - 1 | |
| z - 2\(\frac{2}{3}\) | |
| -6z - 4 |