When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -5c + 4c = -8c - 6z + 7 for c in terms of z.
| 4\(\frac{2}{3}\)z - \(\frac{2}{3}\) | |
| z + \(\frac{1}{4}\) | |
| -3\(\frac{1}{3}\)z + 2\(\frac{1}{3}\) | |
| -4z + 1\(\frac{1}{4}\) |