ASVAB Math Knowledge Practice Test 834871 Results

Your Results Global Average
Questions 5 5
Correct 0 2.93
Score 0% 59%

Review

1

Which of the following is not true about both rectangles and squares?

63% Answer Correctly

the perimeter is the sum of the lengths of all four sides

the area is length x width

the lengths of all sides are equal

all interior angles are right angles


Solution

A rectangle is a parallelogram containing four right angles. Opposite sides (a = c, b = d) are equal and the perimeter is the sum of the lengths of all sides (a + b + c + d) or, comonly, 2 x length x width. The area of a rectangle is length x width. A square is a rectangle with four equal length sides. The perimeter of a square is 4 x length of one side (4s) and the area is the length of one side squared (s2).


2

What is the circumference of a circle with a radius of 19?

70% Answer Correctly
38π
30π
22π

Solution

The formula for circumference is circle diameter x π. Circle diameter is 2 x radius:

c = πd
c = π(2 * r)
c = π(2 * 19)
c = 38π


3

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

obtuse, acute

vertical, supplementary

supplementary, vertical

acute, obtuse


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


4

A(n) __________ is to a parallelogram as a square is to a rectangle.

51% Answer Correctly

triangle

rhombus

trapezoid

quadrilateral


Solution

A rhombus is a parallelogram with four equal-length sides. A square is a rectangle with four equal-length sides.


5

The dimensions of this cylinder are height (h) = 9 and radius (r) = 9. What is the surface area?

48% Answer Correctly
196π
324π
16π
42π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(92) + 2π(9 x 9)
sa = 2π(81) + 2π(81)
sa = (2 x 81)π + (2 x 81)π
sa = 162π + 162π
sa = 324π