| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.74 |
| Score | 0% | 55% |
On this circle, line segment AB is the:
circumference |
|
diameter |
|
chord |
|
radius |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
The dimensions of this trapezoid are a = 4, b = 9, c = 5, d = 9, and h = 3. What is the area?
| 13\(\frac{1}{2}\) | |
| 27 | |
| 16\(\frac{1}{2}\) | |
| 26 |
The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:
a = ½(b + d)(h)
a = ½(9 + 9)(3)
a = ½(18)(3)
a = ½(54) = \( \frac{54}{2} \)
a = 27
Simplify (7a)(7ab) - (6a2)(5b).
| 79ab2 | |
| 154a2b | |
| 19a2b | |
| 154ab2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
(7a)(7ab) - (6a2)(5b)
(7 x 7)(a x a x b) - (6 x 5)(a2 x b)
(49)(a1+1 x b) - (30)(a2b)
49a2b - 30a2b
19a2b
Solve for a:
3a - 3 < \( \frac{a}{5} \)
| a < 1\(\frac{1}{14}\) | |
| a < 1\(\frac{9}{11}\) | |
| a < -3\(\frac{11}{15}\) | |
| a < -\(\frac{2}{9}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
3a - 3 < \( \frac{a}{5} \)
5 x (3a - 3) < a
(5 x 3a) + (5 x -3) < a
15a - 15 < a
15a - 15 - a < 0
15a - a < 15
14a < 15
a < \( \frac{15}{14} \)
a < 1\(\frac{1}{14}\)
Solve for a:
-7a - 5 = \( \frac{a}{9} \)
| -\(\frac{8}{37}\) | |
| \(\frac{24}{41}\) | |
| -\(\frac{45}{64}\) | |
| \(\frac{1}{8}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.
-7a - 5 = \( \frac{a}{9} \)
9 x (-7a - 5) = a
(9 x -7a) + (9 x -5) = a
-63a - 45 = a
-63a - 45 - a = 0
-63a - a = 45
-64a = 45
a = \( \frac{45}{-64} \)
a = -\(\frac{45}{64}\)