When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 5c + 5c = -5c - 4x - 5 for c in terms of x.
| 3\(\frac{1}{2}\)x + 2\(\frac{1}{2}\) | |
| 6x - 1 | |
| -\(\frac{9}{10}\)x - \(\frac{1}{2}\) | |
| -2\(\frac{1}{5}\)x + \(\frac{3}{5}\) |