When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -3c + 5c = 4c + 5z - 2 for c in terms of z.
| -\(\frac{3}{4}\)z - \(\frac{5}{16}\) | |
| z + \(\frac{2}{7}\) | |
| \(\frac{1}{2}\)z + \(\frac{3}{16}\) | |
| -7z - 3 |