When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 7b + 3b = -5b - z + 1 for b in terms of z.
| -\(\frac{1}{3}\)z + \(\frac{1}{12}\) | |
| -\(\frac{1}{6}\)z + \(\frac{5}{6}\) | |
| 1\(\frac{1}{4}\)z - \(\frac{3}{4}\) | |
| \(\frac{1}{4}\)z + \(\frac{1}{3}\) |