| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.96 |
| Score | 0% | 59% |
On this circle, a line segment connecting point A to point D is called:
chord |
|
circumference |
|
radius |
|
diameter |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
What is 2a8 - 8a8?
| 10 | |
| 10a16 | |
| -6 | |
| -6a8 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
2a8 - 8a8 = -6a8
On this circle, line segment AB is the:
diameter |
|
circumference |
|
radius |
|
chord |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Solve for c:
6c - 5 > \( \frac{c}{6} \)
| c > -1\(\frac{14}{31}\) | |
| c > \(\frac{49}{62}\) | |
| c > \(\frac{6}{7}\) | |
| c > 1\(\frac{11}{37}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the > sign and the answer on the other.
6c - 5 > \( \frac{c}{6} \)
6 x (6c - 5) > c
(6 x 6c) + (6 x -5) > c
36c - 30 > c
36c - 30 - c > 0
36c - c > 30
35c > 30
c > \( \frac{30}{35} \)
c > \(\frac{6}{7}\)
If side a = 9, side b = 8, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{113} \) | |
| \( \sqrt{53} \) | |
| \( \sqrt{145} \) | |
| \( \sqrt{26} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 92 + 82
c2 = 81 + 64
c2 = 145
c = \( \sqrt{145} \)