When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3b + 3b = b - 6z + 1 for b in terms of z.
| -1\(\frac{3}{10}\)z - \(\frac{3}{5}\) | |
| -4\(\frac{1}{2}\)z + \(\frac{1}{2}\) | |
| \(\frac{1}{8}\)z + \(\frac{5}{8}\) | |
| -1\(\frac{1}{2}\)z - 1 |