ASVAB Math Knowledge Practice Test 837510 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

The formula for the area of a circle is which of the following?

78% Answer Correctly

a = π r2

a = π d2

a = π d

a = π r


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


2

Which of the following is not a part of PEMDAS, the acronym for math order of operations?

91% Answer Correctly

exponents

pairs

division

addition


Solution

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)


3

Solve -4c - c = -5c - 7z - 1 for c in terms of z.

34% Answer Correctly
-6z - 1
-1\(\frac{1}{13}\)z + \(\frac{2}{13}\)
4z - 1
-\(\frac{1}{5}\)z + 1\(\frac{3}{5}\)

Solution

To solve this equation, isolate the variable for which you are solving (c) on one side of the equation and put everything else on the other side.

-4c - z = -5c - 7z - 1
-4c = -5c - 7z - 1 + z
-4c + 5c = -7z - 1 + z
c = -6z - 1


4

On this circle, line segment AB is the:

71% Answer Correctly

circumference

radius

chord

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

The dimensions of this cylinder are height (h) = 7 and radius (r) = 3. What is the surface area?

48% Answer Correctly
60π
324π
32π
72π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(32) + 2π(3 x 7)
sa = 2π(9) + 2π(21)
sa = (2 x 9)π + (2 x 21)π
sa = 18π + 42π
sa = 60π