When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 2a + 8a = 6a + 5z + 1 for a in terms of z.
| -3\(\frac{2}{3}\)z + 1\(\frac{2}{3}\) | |
| \(\frac{3}{4}\)z - \(\frac{1}{4}\) | |
| 2\(\frac{1}{4}\)z - 1\(\frac{1}{4}\) | |
| \(\frac{1}{7}\)z - \(\frac{1}{7}\) |