ASVAB Math Knowledge Practice Test 838555

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 9c + 6c = -6c - 5z + 4 for c in terms of z.

\(\frac{1}{18}\)z + \(\frac{4}{9}\)
-\(\frac{11}{15}\)z + \(\frac{4}{15}\)
\(\frac{2}{3}\)z + \(\frac{7}{9}\)
-\(\frac{5}{9}\)z - \(\frac{1}{9}\)