ASVAB Math Knowledge Practice Test 838606

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 8a - 3a = -5a + 2z + 5 for a in terms of z.

\(\frac{5}{13}\)z + \(\frac{5}{13}\)
-1\(\frac{3}{14}\)z + \(\frac{3}{14}\)
-1\(\frac{1}{14}\)z + \(\frac{5}{14}\)
\(\frac{1}{3}\)z - 1