ASVAB Math Knowledge Practice Test 840086

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 2c + 3c = 9c + 6y + 3 for c in terms of y.

-\(\frac{3}{7}\)y - \(\frac{3}{7}\)
6y - 4
4\(\frac{1}{2}\)y - 4
\(\frac{1}{2}\)y - 1\(\frac{1}{2}\)