ASVAB Math Knowledge Practice Test 840188

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 4c + 7c = -7c - 2z - 5 for c in terms of z.

-2\(\frac{3}{4}\)z + 1\(\frac{1}{4}\)
2z + \(\frac{6}{7}\)
-1\(\frac{2}{5}\)z + 1\(\frac{3}{5}\)
-\(\frac{9}{11}\)z - \(\frac{5}{11}\)