ASVAB Math Knowledge Practice Test 840915 Results

Your Results Global Average
Questions 5 5
Correct 0 3.57
Score 0% 71%

Review

1

If a = 1, b = 6, c = 2, and d = 8, what is the perimeter of this quadrilateral?

88% Answer Correctly
25
17
22
11

Solution

Perimeter is equal to the sum of the four sides:

p = a + b + c + d
p = 1 + 6 + 2 + 8
p = 17


2

If the area of this square is 81, what is the length of one of the diagonals?

68% Answer Correctly
3\( \sqrt{2} \)
8\( \sqrt{2} \)
9\( \sqrt{2} \)
5\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{81} \) = 9

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 92 + 92
c2 = 162
c = \( \sqrt{162} \) = \( \sqrt{81 x 2} \) = \( \sqrt{81} \) \( \sqrt{2} \)
c = 9\( \sqrt{2} \)


3

A coordinate grid is composed of which of the following?

88% Answer Correctly

all of these

y-axis

origin

x-axis


Solution

The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.


4

Solve for c:
2c - 7 = \( \frac{c}{-3} \)

46% Answer Correctly
4\(\frac{11}{13}\)
3
-1\(\frac{23}{41}\)
\(\frac{12}{49}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

2c - 7 = \( \frac{c}{-3} \)
-3 x (2c - 7) = c
(-3 x 2c) + (-3 x -7) = c
-6c + 21 = c
-6c + 21 - c = 0
-6c - c = -21
-7c = -21
c = \( \frac{-21}{-7} \)
c = 3


5

Simplify (5a)(9ab) + (5a2)(6b).

65% Answer Correctly
15a2b
75a2b
154a2b
75ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(5a)(9ab) + (5a2)(6b)
(5 x 9)(a x a x b) + (5 x 6)(a2 x b)
(45)(a1+1 x b) + (30)(a2b)
45a2b + 30a2b
75a2b