When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c - 6c = -7c + 2x - 1 for c in terms of x.
| \(\frac{1}{4}\)x - 1\(\frac{1}{4}\) | |
| x - \(\frac{3}{5}\) | |
| x - \(\frac{1}{15}\) | |
| \(\frac{4}{5}\)x - \(\frac{1}{10}\) |