| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.91 |
| Score | 0% | 58% |
Solve for c:
4c - 5 < -2 + 3c
| c < -\(\frac{3}{4}\) | |
| c < -1 | |
| c < 3 | |
| c < 1\(\frac{3}{4}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
4c - 5 < -2 + 3c
4c < -2 + 3c + 5
4c - 3c < -2 + 5
c < 3
The endpoints of this line segment are at (-2, -6) and (2, 4). What is the slope-intercept equation for this line?
| y = 2\(\frac{1}{2}\)x - 1 | |
| y = -1\(\frac{1}{2}\)x - 4 | |
| y = -x - 4 | |
| y = 3x + 4 |
The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -6) and (2, 4) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(4.0) - (-6.0)}{(2) - (-2)} \) = \( \frac{10}{4} \)Plugging these values into the slope-intercept equation:
y = 2\(\frac{1}{2}\)x - 1
A trapezoid is a quadrilateral with one set of __________ sides.
parallel |
|
equal length |
|
equal angle |
|
right angle |
A trapezoid is a quadrilateral with one set of parallel sides.
Solve for b:
b2 - 9b + 18 = 0
| 9 or 4 | |
| 3 or 6 | |
| 4 or -2 | |
| 7 or -7 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
b2 - 9b + 18 = 0
(b - 3)(b - 6) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 3) or (b - 6) must equal zero:
If (b - 3) = 0, b must equal 3
If (b - 6) = 0, b must equal 6
So the solution is that b = 3 or 6
What is the area of a circle with a diameter of 10?
| 16π | |
| 25π | |
| 6π | |
| 5π |
The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):
r = \( \frac{d}{2} \)
r = \( \frac{10}{2} \)
r = 5
a = πr2
a = π(52)
a = 25π