ASVAB Math Knowledge Practice Test 845045 Results

Your Results Global Average
Questions 5 5
Correct 0 2.91
Score 0% 58%

Review

1

Solve for c:
4c - 5 < -2 + 3c

54% Answer Correctly
c < -\(\frac{3}{4}\)
c < -1
c < 3
c < 1\(\frac{3}{4}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

4c - 5 < -2 + 3c
4c < -2 + 3c + 5
4c - 3c < -2 + 5
c < 3


2

The endpoints of this line segment are at (-2, -6) and (2, 4). What is the slope-intercept equation for this line?

41% Answer Correctly
y = 2\(\frac{1}{2}\)x - 1
y = -1\(\frac{1}{2}\)x - 4
y = -x - 4
y = 3x + 4

Solution

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -1. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -6) and (2, 4) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(4.0) - (-6.0)}{(2) - (-2)} \) = \( \frac{10}{4} \)
m = 2\(\frac{1}{2}\)

Plugging these values into the slope-intercept equation:

y = 2\(\frac{1}{2}\)x - 1


3

A trapezoid is a quadrilateral with one set of __________ sides.

70% Answer Correctly

parallel

equal length

equal angle

right angle


Solution

A trapezoid is a quadrilateral with one set of parallel sides.


4

Solve for b:
b2 - 9b + 18 = 0

57% Answer Correctly
9 or 4
3 or 6
4 or -2
7 or -7

Solution

The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:

b2 - 9b + 18 = 0
(b - 3)(b - 6) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (b - 3) or (b - 6) must equal zero:

If (b - 3) = 0, b must equal 3
If (b - 6) = 0, b must equal 6

So the solution is that b = 3 or 6


5

What is the area of a circle with a diameter of 10?

69% Answer Correctly
16π
25π
6π
5π

Solution

The formula for area is πr2. Radius is circle \( \frac{diameter}{2} \):

r = \( \frac{d}{2} \)
r = \( \frac{10}{2} \)
r = 5
a = πr2
a = π(52)
a = 25π