ASVAB Math Knowledge Practice Test 845890 Results

Your Results Global Average
Questions 5 5
Correct 0 3.16
Score 0% 63%

Review

1

Which types of triangles will always have at least two sides of equal length?

54% Answer Correctly

equilateral, isosceles and right

equilateral and isosceles

equilateral and right

isosceles and right


Solution

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.


2

Solve for a:
-7a - 7 = -8 + 7a

59% Answer Correctly
\(\frac{1}{3}\)
1\(\frac{2}{5}\)
-2\(\frac{1}{2}\)
\(\frac{1}{14}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-7a - 7 = -8 + 7a
-7a = -8 + 7a + 7
-7a - 7a = -8 + 7
-14a = -1
a = \( \frac{-1}{-14} \)
a = \(\frac{1}{14}\)


3

When two lines intersect, adjacent angles are __________ (they add up to 180°) and angles across from either other are __________ (they're equal).

60% Answer Correctly

obtuse, acute

acute, obtuse

supplementary, vertical

vertical, supplementary


Solution

Angles around a line add up to 180°. Angles around a point add up to 360°. When two lines intersect, adjacent angles are supplementary (they add up to 180°) and angles across from either other are vertical (they're equal).


4

What is 5a6 + 6a6?

75% Answer Correctly
11a6
11a12
11
30a12

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

5a6 + 6a6 = 11a6


5

If the area of this square is 36, what is the length of one of the diagonals?

68% Answer Correctly
\( \sqrt{2} \)
6\( \sqrt{2} \)
3\( \sqrt{2} \)
7\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{36} \) = 6

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 62 + 62
c2 = 72
c = \( \sqrt{72} \) = \( \sqrt{36 x 2} \) = \( \sqrt{36} \) \( \sqrt{2} \)
c = 6\( \sqrt{2} \)