ASVAB Math Knowledge Practice Test 847094 Results

Your Results Global Average
Questions 5 5
Correct 0 3.50
Score 0% 70%

Review

1

If side x = 14cm, side y = 13cm, and side z = 13cm what is the perimeter of this triangle?

84% Answer Correctly
28cm
40cm
31cm
38cm

Solution

The perimeter of a triangle is the sum of the lengths of its sides:

p = x + y + z
p = 14cm + 13cm + 13cm = 40cm


2

The dimensions of this trapezoid are a = 4, b = 2, c = 7, d = 8, and h = 3. What is the area?

50% Answer Correctly
34
15
30
36

Solution

The area of a trapezoid is one-half the sum of the lengths of the parallel sides multiplied by the height:

a = ½(b + d)(h)
a = ½(2 + 8)(3)
a = ½(10)(3)
a = ½(30) = \( \frac{30}{2} \)
a = 15


3

On this circle, line segment AB is the:

70% Answer Correctly

circumference

chord

radius

diameter


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


4

The formula for the area of a circle is which of the following?

77% Answer Correctly

a = π d2

a = π d

a = π r2

a = π r


Solution

The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.


5

If the area of this square is 1, what is the length of one of the diagonals?

68% Answer Correctly
8\( \sqrt{2} \)
\( \sqrt{2} \)
4\( \sqrt{2} \)
6\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)