ASVAB Math Knowledge Practice Test 847200 Results

Your Results Global Average
Questions 5 5
Correct 0 3.05
Score 0% 61%

Review

1

A right angle measures:

90% Answer Correctly

45°

360°

90°

180°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.


2

Solve for z:
z2 + 3z - 12 = -4z - 4

48% Answer Correctly
2 or -2
8 or -2
1 or -8
4 or -3

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

z2 + 3z - 12 = -4z - 4
z2 + 3z - 12 + 4 = -4z
z2 + 3z + 4z - 8 = 0
z2 + 7z - 8 = 0

Next, factor the quadratic equation:

z2 + 7z - 8 = 0
(z - 1)(z + 8) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (z - 1) or (z + 8) must equal zero:

If (z - 1) = 0, z must equal 1
If (z + 8) = 0, z must equal -8

So the solution is that z = 1 or -8


3

The endpoints of this line segment are at (-2, 1) and (2, -7). What is the slope of this line?

46% Answer Correctly
-3
3
-2
-1

Solution

The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 1) and (2, -7) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-7.0) - (1.0)}{(2) - (-2)} \) = \( \frac{-8}{4} \)
m = -2


4

If angle a = 25° and angle b = 68° what is the length of angle d?

56% Answer Correctly
153°
155°
138°
139°

Solution

An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite:

d° = b° + c°

To find angle c, remember that the sum of the interior angles of a triangle is 180°:

180° = a° + b° + c°
c° = 180° - a° - b°
c° = 180° - 25° - 68° = 87°

So, d° = 68° + 87° = 155°

A shortcut to get this answer is to remember that angles around a line add up to 180°:

a° + d° = 180°
d° = 180° - a°
d° = 180° - 25° = 155°


5

Simplify (3a)(4ab) + (9a2)(3b).

65% Answer Correctly
15a2b
84ab2
39a2b
-15ab2

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(3a)(4ab) + (9a2)(3b)
(3 x 4)(a x a x b) + (9 x 3)(a2 x b)
(12)(a1+1 x b) + (27)(a2b)
12a2b + 27a2b
39a2b