ASVAB Math Knowledge Practice Test 852325 Results

Your Results Global Average
Questions 5 5
Correct 0 3.17
Score 0% 63%

Review

1

Solve for y:
y2 - 15y + 85 = 3y + 4

48% Answer Correctly
1 or -6
9
9 or 5
-6 or -9

Solution

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

y2 - 15y + 85 = 3y + 4
y2 - 15y + 85 - 4 = 3y
y2 - 15y - 3y + 81 = 0
y2 - 18y + 81 = 0

Next, factor the quadratic equation:

y2 - 18y + 81 = 0
(y - 9)(y - 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, (y - 9) must equal zero:

If (y - 9) = 0, y must equal 9

So the solution is that y = 9


2

A quadrilateral is a shape with __________ sides.

90% Answer Correctly

2

3

4

5


Solution

A quadrilateral is a shape with four sides. The perimeter of a quadrilateral is the sum of the lengths of its four sides.


3

Solve -6b - 8b = 5b - 2x - 7 for b in terms of x.

34% Answer Correctly
3\(\frac{1}{2}\)x - 4
-11x - 2
\(\frac{1}{2}\)x + \(\frac{2}{3}\)
-\(\frac{6}{11}\)x + \(\frac{7}{11}\)

Solution

To solve this equation, isolate the variable for which you are solving (b) on one side of the equation and put everything else on the other side.

-6b - 8x = 5b - 2x - 7
-6b = 5b - 2x - 7 + 8x
-6b - 5b = -2x - 7 + 8x
-11b = 6x - 7
b = \( \frac{6x - 7}{-11} \)
b = \( \frac{6x}{-11} \) + \( \frac{-7}{-11} \)
b = -\(\frac{6}{11}\)x + \(\frac{7}{11}\)


4

On this circle, line segment AB is the:

70% Answer Correctly

radius

circumference

diameter

chord


Solution

A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).


5

What is 8a6 - 4a6?

73% Answer Correctly
32a6
a612
4a6
12

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

8a6 - 4a6 = 4a6