| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.31 |
| Score | 0% | 66% |
The endpoints of this line segment are at (-2, 3) and (2, 1). What is the slope of this line?
| -1 | |
| -2 | |
| 2 | |
| -\(\frac{1}{2}\) |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 3) and (2, 1) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(1.0) - (3.0)}{(2) - (-2)} \) = \( \frac{-2}{4} \)If side a = 6, side b = 5, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{53} \) | |
| \( \sqrt{85} \) | |
| \( \sqrt{29} \) | |
| \( \sqrt{61} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 62 + 52
c2 = 36 + 25
c2 = 61
c = \( \sqrt{61} \)
If the area of this square is 81, what is the length of one of the diagonals?
| 4\( \sqrt{2} \) | |
| 7\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 9\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{81} \) = 9
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 92 + 92
c2 = 162
c = \( \sqrt{162} \) = \( \sqrt{81 x 2} \) = \( \sqrt{81} \) \( \sqrt{2} \)
c = 9\( \sqrt{2} \)
If a = c = 6, b = d = 4, what is the area of this rectangle?
| 18 | |
| 24 | |
| 1 | |
| 32 |
The area of a rectangle is equal to its length x width:
a = l x w
a = a x b
a = 6 x 4
a = 24
What is 7a4 + 8a4?
| 15 | |
| -1 | |
| 56a4 | |
| 15a4 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
7a4 + 8a4 = 15a4