When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 10c - 3c = 9c - 8x - 1 for c in terms of x.
| -\(\frac{6}{7}\)x + \(\frac{9}{14}\) | |
| -6\(\frac{1}{2}\)x - 1\(\frac{1}{2}\) | |
| -5x - 1 | |
| -1\(\frac{1}{3}\)x + 1 |