| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.48 |
| Score | 0% | 70% |
The formula for the area of a circle is which of the following?
a = π r |
|
a = π d |
|
a = π d2 |
|
a = π r2 |
The circumference of a circle is the distance around its perimeter and equals π (approx. 3.14159) x diameter: c = π d. The area of a circle is π x (radius)2 : a = π r2.
Simplify 7a x 8b.
| 56ab | |
| 56\( \frac{b}{a} \) | |
| 56\( \frac{a}{b} \) | |
| 56a2b2 |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
7a x 8b = (7 x 8) (a x b) = 56ab
What is 7a2 - 3a2?
| 4a2 | |
| 21a2 | |
| 4 | |
| a24 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
7a2 - 3a2 = 4a2
If the area of this square is 9, what is the length of one of the diagonals?
| 7\( \sqrt{2} \) | |
| 5\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| 3\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{9} \) = 3
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 32 + 32
c2 = 18
c = \( \sqrt{18} \) = \( \sqrt{9 x 2} \) = \( \sqrt{9} \) \( \sqrt{2} \)
c = 3\( \sqrt{2} \)
The endpoints of this line segment are at (-2, -2) and (2, -6). What is the slope of this line?
| -1 | |
| -2 | |
| 1\(\frac{1}{2}\) | |
| 3 |
The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, -2) and (2, -6) so the slope becomes:
m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-6.0) - (-2.0)}{(2) - (-2)} \) = \( \frac{-4}{4} \)