ASVAB Math Knowledge Practice Test 857681 Results

Your Results Global Average
Questions 5 5
Correct 0 2.94
Score 0% 59%

Review

1

The dimensions of this cube are height (h) = 1, length (l) = 5, and width (w) = 5. What is the surface area?

51% Answer Correctly
64
70
108
62

Solution

The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):

sa = 2lw + 2wh + 2lh
sa = (2 x 5 x 5) + (2 x 5 x 1) + (2 x 5 x 1)
sa = (50) + (10) + (10)
sa = 70


2

A cylinder with a radius (r) and a height (h) has a surface area of:

52% Answer Correctly

2(π r2) + 2π rh

π r2h

π r2h2

4π r2


Solution

A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.


3

A right angle measures:

89% Answer Correctly

90°

45°

180°

360°


Solution

A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.


4

Which of the following statements about a triangle is not true?

57% Answer Correctly

sum of interior angles = 180°

exterior angle = sum of two adjacent interior angles

area = ½bh

perimeter = sum of side lengths


Solution

A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.


5

Solve for y:
-6y + 8 < \( \frac{y}{6} \)

44% Answer Correctly
y < \(\frac{35}{62}\)
y < 1\(\frac{11}{37}\)
y < -1\(\frac{1}{7}\)
y < -1\(\frac{1}{19}\)

Solution

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.

-6y + 8 < \( \frac{y}{6} \)
6 x (-6y + 8) < y
(6 x -6y) + (6 x 8) < y
-36y + 48 < y
-36y + 48 - y < 0
-36y - y < -48
-37y < -48
y < \( \frac{-48}{-37} \)
y < 1\(\frac{11}{37}\)