| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.94 |
| Score | 0% | 59% |
The dimensions of this cube are height (h) = 1, length (l) = 5, and width (w) = 5. What is the surface area?
| 64 | |
| 70 | |
| 108 | |
| 62 |
The surface area of a cube is (2 x length x width) + (2 x width x height) + (2 x length x height):
sa = 2lw + 2wh + 2lh
sa = (2 x 5 x 5) + (2 x 5 x 1) + (2 x 5 x 1)
sa = (50) + (10) + (10)
sa = 70
A cylinder with a radius (r) and a height (h) has a surface area of:
2(π r2) + 2π rh |
|
π r2h |
|
π r2h2 |
|
4π r2 |
A cylinder is a solid figure with straight parallel sides and a circular or oval cross section with a radius (r) and a height (h). The volume of a cylinder is π r2h and the surface area is 2(π r2) + 2π rh.
A right angle measures:
90° |
|
45° |
|
180° |
|
360° |
A right angle measures 90 degrees and is the intersection of two perpendicular lines. In diagrams, a right angle is indicated by a small box completing a square with the perpendicular lines.
Which of the following statements about a triangle is not true?
sum of interior angles = 180° |
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exterior angle = sum of two adjacent interior angles |
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area = ½bh |
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perimeter = sum of side lengths |
A triangle is a three-sided polygon. It has three interior angles that add up to 180° (a + b + c = 180°). An exterior angle of a triangle is equal to the sum of the two interior angles that are opposite (d = b + c). The perimeter of a triangle is equal to the sum of the lengths of its three sides, the height of a triangle is equal to the length from the base to the opposite vertex (angle) and the area equals one-half triangle base x height: a = ½ base x height.
Solve for y:
-6y + 8 < \( \frac{y}{6} \)
| y < \(\frac{35}{62}\) | |
| y < 1\(\frac{11}{37}\) | |
| y < -1\(\frac{1}{7}\) | |
| y < -1\(\frac{1}{19}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
-6y + 8 < \( \frac{y}{6} \)
6 x (-6y + 8) < y
(6 x -6y) + (6 x 8) < y
-36y + 48 < y
-36y + 48 - y < 0
-36y - y < -48
-37y < -48
y < \( \frac{-48}{-37} \)
y < 1\(\frac{11}{37}\)