ASVAB Math Knowledge Practice Test 857787

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 9a - 5a = 3a - 2z + 6 for a in terms of z.

\(\frac{1}{2}\)z + 1
-z - \(\frac{1}{9}\)
\(\frac{5}{11}\)z - \(\frac{9}{11}\)
\(\frac{9}{10}\)z + \(\frac{3}{5}\)