ASVAB Math Knowledge Practice Test 859607

Question 4 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -7a + 6a = 6a + 5y + 3 for a in terms of y.

\(\frac{1}{16}\)y - \(\frac{7}{16}\)
-1\(\frac{6}{7}\)y + \(\frac{2}{7}\)
-7y + 1
\(\frac{1}{13}\)y - \(\frac{3}{13}\)