ASVAB Math Knowledge Practice Test 86138

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve 3b + 6b = 6b + 6z + 9 for b in terms of z.

-5z - 5
6\(\frac{1}{2}\)z - 4\(\frac{1}{2}\)
\(\frac{1}{2}\)z - \(\frac{1}{2}\)
z - 3