ASVAB Math Knowledge Practice Test 862522 Results

Your Results Global Average
Questions 5 5
Correct 0 3.29
Score 0% 66%

Review

1

The dimensions of this cylinder are height (h) = 7 and radius (r) = 6. What is the surface area?

48% Answer Correctly
156π
10π
108π
56π

Solution

The surface area of a cylinder is 2πr2 + 2πrh:

sa = 2πr2 + 2πrh
sa = 2π(62) + 2π(6 x 7)
sa = 2π(36) + 2π(42)
sa = (2 x 36)π + (2 x 42)π
sa = 72π + 84π
sa = 156π


2

If the area of this square is 49, what is the length of one of the diagonals?

68% Answer Correctly
7\( \sqrt{2} \)
2\( \sqrt{2} \)
8\( \sqrt{2} \)
3\( \sqrt{2} \)

Solution

To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:

a = s2

so the length of one side of the square is:

s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7

The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:

c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)


3

What is 7a4 + 4a4?

75% Answer Correctly
11
11a4
28a4
3a8

Solution

To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.

7a4 + 4a4 = 11a4


4

Simplify (8a)(6ab) - (7a2)(6b).

62% Answer Correctly
-6ab2
182a2b
90ab2
6a2b

Solution

To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.

(8a)(6ab) - (7a2)(6b)
(8 x 6)(a x a x b) - (7 x 6)(a2 x b)
(48)(a1+1 x b) - (42)(a2b)
48a2b - 42a2b
6a2b


5

Breaking apart a quadratic expression into a pair of binomials is called:

74% Answer Correctly

normalizing

deconstructing

squaring

factoring


Solution

To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.