When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve b + 6b = -9b + 2z - 1 for b in terms of z.
| z - \(\frac{1}{12}\) | |
| -1\(\frac{3}{10}\)z - \(\frac{4}{5}\) | |
| 1\(\frac{2}{3}\)z - \(\frac{1}{3}\) | |
| -\(\frac{2}{5}\)z - \(\frac{1}{10}\) |