| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.21 |
| Score | 0% | 64% |
The formula for volume of a cube in terms of height (h), length (l), and width (w) is which of the following?
h x l x w |
|
h2 x l2 x w2 |
|
lw x wh + lh |
|
2lw x 2wh + 2lh |
A cube is a rectangular solid box with a height (h), length (l), and width (w). The volume is h x l x w and the surface area is 2lw x 2wh + 2lh.
On this circle, line segment CD is the:
chord |
|
radius |
|
diameter |
|
circumference |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
The dimensions of this cylinder are height (h) = 7 and radius (r) = 6. What is the volume?
| 252π | |
| 27π | |
| 7π | |
| 45π |
The volume of a cylinder is πr2h:
v = πr2h
v = π(62 x 7)
v = 252π
What is 5a5 + 7a5?
| a510 | |
| 12 | |
| -2a10 | |
| 12a5 |
To combine like terms, add or subtract the coefficients (the numbers that come before the variables) of terms that have the same variable raised to the same exponent.
5a5 + 7a5 = 12a5
If the area of this square is 49, what is the length of one of the diagonals?
| 4\( \sqrt{2} \) | |
| 7\( \sqrt{2} \) | |
| 8\( \sqrt{2} \) | |
| \( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{49} \) = 7
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 72 + 72
c2 = 98
c = \( \sqrt{98} \) = \( \sqrt{49 x 2} \) = \( \sqrt{49} \) \( \sqrt{2} \)
c = 7\( \sqrt{2} \)