When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 6c + 5c = 4c - 4x + 5 for c in terms of x.
| -2x - 2\(\frac{1}{3}\) | |
| 6x + 4 | |
| \(\frac{3}{11}\)x - \(\frac{5}{11}\) | |
| -4\(\frac{1}{2}\)x + 2\(\frac{1}{2}\) |