When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 9a + 3a = 2a + 2z - 5 for a in terms of z.
| 1\(\frac{5}{6}\)z + \(\frac{1}{2}\) | |
| -\(\frac{2}{5}\)z + \(\frac{1}{2}\) | |
| -\(\frac{1}{5}\)z - \(\frac{4}{5}\) | |
| -\(\frac{1}{7}\)z - \(\frac{5}{7}\) |