When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3c + 8c = -8c - 4x + 8 for c in terms of x.
| \(\frac{1}{4}\)x - 1\(\frac{1}{8}\) | |
| -1\(\frac{1}{11}\)x + \(\frac{8}{11}\) | |
| \(\frac{5}{12}\)x - \(\frac{7}{12}\) | |
| 7x - 1 |