When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -4c - 3c = c - 4x + 3 for c in terms of x.
| -3x - \(\frac{1}{3}\) | |
| \(\frac{1}{5}\)x - \(\frac{3}{5}\) | |
| \(\frac{7}{8}\)x + 1 | |
| \(\frac{4}{5}\)x - 1 |