When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 8a + 6a = -8a + 2z - 5 for a in terms of z.
| -4z + 3 | |
| -\(\frac{1}{4}\)z - \(\frac{5}{16}\) | |
| -\(\frac{3}{4}\)z + 1\(\frac{1}{2}\) | |
| 1\(\frac{1}{2}\)z + \(\frac{2}{5}\) |