ASVAB Math Knowledge Practice Test 869249

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -3a + 3a = 2a - 5z - 5 for a in terms of z.

\(\frac{4}{5}\)z - 1\(\frac{1}{5}\)
2\(\frac{1}{2}\)z - \(\frac{3}{4}\)
z - 3
1\(\frac{3}{5}\)z + 1