| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
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Simplify (y + 6)(y - 3)
| y2 - 3y - 18 | |
| y2 - 9y + 18 | |
| y2 + 3y - 18 | |
| y2 + 9y + 18 |
To multiply binomials, use the FOIL method. FOIL stands for First, Outside, Inside, Last and refers to the position of each term in the parentheses:
(y + 6)(y - 3)
(y x y) + (y x -3) + (6 x y) + (6 x -3)
y2 - 3y + 6y - 18
y2 + 3y - 18
On this circle, line segment AB is the:
radius |
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circumference |
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chord |
|
diameter |
A circle is a figure in which each point around its perimeter is an equal distance from the center. The radius of a circle is the distance between the center and any point along its perimeter. A chord is a line segment that connects any two points along its perimeter. The diameter of a circle is the length of a chord that passes through the center of the circle and equals twice the circle's radius (2r).
Solve for y:
y2 - 3y - 54 = 0
| -6 or 9 | |
| 4 or -6 | |
| -5 or -8 | |
| -7 or -9 |
The first step to solve a quadratic equation that's set to zero is to factor the quadratic equation:
y2 - 3y - 54 = 0
(y + 6)(y - 9) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (y + 6) or (y - 9) must equal zero:
If (y + 6) = 0, y must equal -6
If (y - 9) = 0, y must equal 9
So the solution is that y = -6 or 9
Solve for b:
b - 9 < \( \frac{b}{-1} \)
| b < -\(\frac{1}{2}\) | |
| b < \(\frac{16}{65}\) | |
| b < 4\(\frac{1}{2}\) | |
| b < \(\frac{12}{35}\) |
To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the < sign and the answer on the other.
b - 9 < \( \frac{b}{-1} \)
-1 x (b - 9) < b
(-1 x b) + (-1 x -9) < b
-b + 9 < b
-b + 9 - b < 0
-b - b < -9
-2b < -9
b < \( \frac{-9}{-2} \)
b < 4\(\frac{1}{2}\)
If the length of AB equals the length of BD, point B __________ this line segment.
trisects |
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midpoints |
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intersects |
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bisects |
A line segment is a portion of a line with a measurable length. The midpoint of a line segment is the point exactly halfway between the endpoints. The midpoint bisects (cuts in half) the line segment.