When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve 3b + 5b = b + 8z + 1 for b in terms of z.
| z + \(\frac{1}{2}\) | |
| 1\(\frac{1}{2}\)z + \(\frac{1}{2}\) | |
| -2\(\frac{3}{4}\)z - 1\(\frac{3}{4}\) | |
| -3\(\frac{2}{3}\)z - 1\(\frac{1}{3}\) |