To solve this equation, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

-4b(b - x)
-4(-8)(-8 + 8)
-4(-8)(0)
(32)(0)
0

The coordinate grid is composed of a horizontal x-axis and a vertical y-axis. The center of the grid, where the x-axis and y-axis meet, is called the origin.

An isosceles triangle has two sides of equal length. An equilateral triangle has three sides of equal length. In a right triangle, two sides meet at a right angle.

The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:

a² + 14a + 10 = 4a + 1
a² + 14a + 10 - 1 = 4a
a² + 14a - 4a + 9 = 0
a² + 10a + 9 = 0

Next, factor the quadratic equation:

a² + 10a + 9 = 0
(a + 1)(a + 9) = 0

For this expression to be true, the left side of the expression must equal zero. Therefore, either (a + 1) or (a + 9) must equal zero:

If (a + 1) = 0, a must equal -1
If (a + 9) = 0, a must equal -9

So the solution is that a = -1 or -9

You need to find the value of a so solve the first equation in terms of y:

-7a + y = 6
y = 6 + 7a

then substitute the result (6 - -7a) into the second equation:

-5a - 4(6 + 7a) = -5
-5a + (-4 x 6) + (-4 x 7a) = -5
-5a - 24 - 28a = -5
-5a - 28a = -5 + 24
-33a = 19
a = \( \frac{19}{-33} \)
a = -\(\frac{19}{33}\)