ASVAB Math Knowledge Practice Test 871868

Question 3 of 5
Two Variables

When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)

Solve -2c + 7c = 7c - 5z - 1 for c in terms of z.

2z - \(\frac{1}{5}\)
1\(\frac{1}{3}\)z + \(\frac{1}{9}\)
\(\frac{9}{13}\)z - \(\frac{2}{13}\)
\(\frac{4}{5}\)z + 1\(\frac{1}{5}\)