| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.40 |
| Score | 0% | 68% |
Simplify 2a x 2b.
| 4a2b2 | |
| 4\( \frac{b}{a} \) | |
| 4\( \frac{a}{b} \) | |
| 4ab |
To multiply monomials, multiply the coefficients (the numbers that come before the variables) of each term, add the exponents of like variables, and multiply the different variables together.
2a x 2b = (2 x 2) (a x b) = 4ab
Breaking apart a quadratic expression into a pair of binomials is called:
factoring |
|
normalizing |
|
squaring |
|
deconstructing |
To factor a quadratic expression, apply the FOIL (First, Outside, Inside, Last) method in reverse.
If side a = 1, side b = 4, what is the length of the hypotenuse of this right triangle?
| \( \sqrt{89} \) | |
| \( \sqrt{17} \) | |
| \( \sqrt{53} \) | |
| \( \sqrt{117} \) |
According to the Pythagorean theorem, the hypotenuse squared is equal to the sum of the two perpendicular sides squared:
c2 = a2 + b2
c2 = 12 + 42
c2 = 1 + 16
c2 = 17
c = \( \sqrt{17} \)
Solve for b:
b2 - 6b - 45 = -5b - 3
| -6 or 7 | |
| 8 or -7 | |
| -3 or -9 | |
| 6 or 6 |
The first step to solve a quadratic expression that's not set to zero is to solve the equation so that it is set to zero:
b2 - 6b - 45 = -5b - 3
b2 - 6b - 45 + 3 = -5b
b2 - 6b + 5b - 42 = 0
b2 - b - 42 = 0
Next, factor the quadratic equation:
b2 - b - 42 = 0
(b + 6)(b - 7) = 0
For this expression to be true, the left side of the expression must equal zero. Therefore, either (b + 6) or (b - 7) must equal zero:
If (b + 6) = 0, b must equal -6
If (b - 7) = 0, b must equal 7
So the solution is that b = -6 or 7
If the area of this square is 1, what is the length of one of the diagonals?
| 8\( \sqrt{2} \) | |
| 2\( \sqrt{2} \) | |
| \( \sqrt{2} \) | |
| 3\( \sqrt{2} \) |
To find the diagonal we need to know the length of one of the square's sides. We know the area and the area of a square is the length of one side squared:
a = s2
so the length of one side of the square is:
s = \( \sqrt{a} \) = \( \sqrt{1} \) = 1
The Pythagorean theorem defines the square of the hypotenuse (diagonal) of a triangle with a right angle as the sum of the squares of the other two sides:
c2 = a2 + b2
c2 = 12 + 12
c2 = 2
c = \( \sqrt{2} \)