When solving an equation with two variables, replace the variables with the values given and then solve the now variable-free equation. (Remember order of operations, PEMDAS, Parentheses, Exponents, Multiplication/Division, Addition/Subtraction.)
Solve -c - 5c = 4c - 8z - 5 for c in terms of z.
| \(\frac{3}{5}\)z + 1 | |
| -1\(\frac{1}{9}\)z - \(\frac{1}{9}\) | |
| \(\frac{2}{9}\)z - 1 | |
| 1\(\frac{1}{4}\)z + \(\frac{1}{4}\) |